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13110111224449 is a prime number
BaseRepresentation
bin1011111011000110111110…
…0001011100001010000001
31201102022111012012021220121
42332301233201130022001
53204244001433140244
643514411342140241
72522113530513361
oct276615741341201
951368435167817
1013110111224449
1141a4a70008438
1215789b1881681
13741380228ab5
14334765cbc9a1
1517b0563eec84
hexbec6f85c281

13110111224449 has 2 divisors, whose sum is σ = 13110111224450. Its totient is φ = 13110111224448.

The previous prime is 13110111224333. The next prime is 13110111224549. The reversal of 13110111224449 is 94442211101131.

13110111224449 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13042390530625 + 67720693824 = 3611425^2 + 260232^2 .

It is a cyclic number.

It is not a de Polignac number, because 13110111224449 - 27 = 13110111224321 is a prime.

It is not a weakly prime, because it can be changed into another prime (13110111224149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555055612224 + 6555055612225.

It is an arithmetic number, because the mean of its divisors is an integer number (6555055612225).

Almost surely, 213110111224449 is an apocalyptic number.

It is an amenable number.

13110111224449 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110111224449 is an equidigital number, since it uses as much as digits as its factorization.

13110111224449 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 34.

The spelling of 13110111224449 in words is "thirteen trillion, one hundred ten billion, one hundred eleven million, two hundred twenty-four thousand, four hundred forty-nine".