Base | Representation |
---|---|
bin | 1011111011000110111110… |
… | …0100011110011000100001 |
3 | 1201102022111020200201012111 |
4 | 2332301233210132120201 |
5 | 3204244002134120001 |
6 | 43514411411155321 |
7 | 2522113540335643 |
oct | 276615744363041 |
9 | 51368436621174 |
10 | 13110112020001 |
11 | 41a4a70501117 |
12 | 15789b1ba5b41 |
13 | 741380446c39 |
14 | 334766048893 |
15 | 17b05650a851 |
hex | bec6f91e621 |
13110112020001 has 2 divisors, whose sum is σ = 13110112020002. Its totient is φ = 13110112020000.
The previous prime is 13110112019987. The next prime is 13110112020023. The reversal of 13110112020001 is 10002021101131.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10966959489600 + 2143152530401 = 3311640^2 + 1463951^2 .
It is a cyclic number.
It is not a de Polignac number, because 13110112020001 - 225 = 13110078465569 is a prime.
It is not a weakly prime, because it can be changed into another prime (13110112020601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555056010000 + 6555056010001.
It is an arithmetic number, because the mean of its divisors is an integer number (6555056010001).
Almost surely, 213110112020001 is an apocalyptic number.
It is an amenable number.
13110112020001 is a deficient number, since it is larger than the sum of its proper divisors (1).
13110112020001 is an equidigital number, since it uses as much as digits as its factorization.
13110112020001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 13.
Adding to 13110112020001 its reverse (10002021101131), we get a palindrome (23112133121132).
The spelling of 13110112020001 in words is "thirteen trillion, one hundred ten billion, one hundred twelve million, twenty thousand, one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •