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131101120343423 is a prime number
BaseRepresentation
bin11101110011110001011011…
…101101010010110101111111
3122012012010220111012101202102
4131303301123231102311333
5114140430043301442143
61142455005004215315
736420512656201406
oct3563613355226577
9565163814171672
10131101120343423
11388557446a887a
1212854337b3a53b
13581ca234b4959
14245348437c63d
15102539359d0b8
hex773c5bb52d7f

131101120343423 has 2 divisors, whose sum is σ = 131101120343424. Its totient is φ = 131101120343422.

The previous prime is 131101120343411. The next prime is 131101120343477. The reversal of 131101120343423 is 324343021101131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131101120343423 - 24 = 131101120343407 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131101120343623) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65550560171711 + 65550560171712.

It is an arithmetic number, because the mean of its divisors is an integer number (65550560171712).

Almost surely, 2131101120343423 is an apocalyptic number.

131101120343423 is a deficient number, since it is larger than the sum of its proper divisors (1).

131101120343423 is an equidigital number, since it uses as much as digits as its factorization.

131101120343423 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 131101120343423 its reverse (324343021101131), we get a palindrome (455444141444554).

The spelling of 131101120343423 in words is "one hundred thirty-one trillion, one hundred one billion, one hundred twenty million, three hundred forty-three thousand, four hundred twenty-three".