13110112101761 has 2 divisors, whose sum is σ = 13110112101762. Its totient is φ = 13110112101760.

The previous prime is 13110112101743. The next prime is 13110112101763. The reversal of 13110112101761 is 16710121101131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12374522849536 + 735589252225 = 3517744^2 + 857665^2 .

It is a cyclic number.

It is not a de Polignac number, because 13110112101761 - 2³⁸ = 12835234194817 is a prime.

It is a super-2 number, since 2×13110112101761² (a number of 27 digits) contains 22 as substring.

Together with 13110112101763, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13110112101761.

It is not a weakly prime, because it can be changed into another prime (13110112101763) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555056050880 + 6555056050881.

It is an arithmetic number, because the mean of its divisors is an integer number (6555056050881).

Almost surely, 2^{13110112101761} is an apocalyptic number.

It is an amenable number.

13110112101761 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110112101761 is an equidigital number, since it uses as much as digits as its factorization.

13110112101761 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252, while the sum is 26.

Adding to 13110112101761 its reverse (16710121101131), we get a palindrome (29820233202892).

The spelling of 13110112101761 in words is "thirteen trillion, one hundred ten billion, one hundred twelve million, one hundred one thousand, seven hundred sixty-one".