Base | Representation |
---|---|
bin | 10011000100111110011… |
… | …010011011010001101100 |
3 | 11122022221200122010121101 |
4 | 103010332122123101230 |
5 | 132434423101441030 |
6 | 2442134244012444 |
7 | 163501050216253 |
oct | 23047632332154 |
9 | 4568850563541 |
10 | 1311012140140 |
11 | 465aa71a205a |
12 | 1920bb391124 |
13 | 968216b27b1 |
14 | 4764bcd979a |
15 | 24180ab17ca |
hex | 1313e69b46c |
1311012140140 has 12 divisors (see below), whose sum is σ = 2753125494336. Its totient is φ = 524404856048.
The previous prime is 1311012140101. The next prime is 1311012140143. The reversal of 1311012140140 is 410412101131.
It is not an unprimeable number, because it can be changed into a prime (1311012140143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32775303484 + ... + 32775303523.
It is an arithmetic number, because the mean of its divisors is an integer number (229427124528).
Almost surely, 21311012140140 is an apocalyptic number.
1311012140140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1311012140140 is an abundant number, since it is smaller than the sum of its proper divisors (1442113354196).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1311012140140 is a wasteful number, since it uses less digits than its factorization.
1311012140140 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65550607016 (or 65550607014 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 1311012140140 its reverse (410412101131), we get a palindrome (1721424241271).
The spelling of 1311012140140 in words is "one trillion, three hundred eleven billion, twelve million, one hundred forty thousand, one hundred forty".
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