Base | Representation |
---|---|
bin | 10011000100111110011… |
… | …010110100011100001110 |
3 | 11122022221200211100222221 |
4 | 103010332122310130032 |
5 | 132434423113240324 |
6 | 2442134250125554 |
7 | 163501051125622 |
oct | 23047632643416 |
9 | 4568850740887 |
10 | 1311012243214 |
11 | 465aa7262543 |
12 | 1920bb4208ba |
13 | 9682171a69b |
14 | 4764bd25182 |
15 | 24180ad20e4 |
hex | 1313e6b470e |
1311012243214 has 4 divisors (see below), whose sum is σ = 1966518364824. Its totient is φ = 655506121606.
The previous prime is 1311012243209. The next prime is 1311012243221. The reversal of 1311012243214 is 4123422101131.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 327753060802 + ... + 327753060805.
It is an arithmetic number, because the mean of its divisors is an integer number (491629591206).
Almost surely, 21311012243214 is an apocalyptic number.
1311012243214 is a deficient number, since it is larger than the sum of its proper divisors (655506121610).
1311012243214 is an equidigital number, since it uses as much as digits as its factorization.
1311012243214 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 655506121609.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1311012243214 its reverse (4123422101131), we get a palindrome (5434434344345).
The spelling of 1311012243214 in words is "one trillion, three hundred eleven billion, twelve million, two hundred forty-three thousand, two hundred fourteen".
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