131101230206047 has 2 divisors, whose sum is σ = 131101230206048. Its totient is φ = 131101230206046.

The previous prime is 131101230206029. The next prime is 131101230206077. The reversal of 131101230206047 is 740602032101131.

It is a weak prime.

It is an emirp because it is prime and its reverse (740602032101131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131101230206047 - 2³⁵ = 131066870467679 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131101230206077) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65550615103023 + 65550615103024.

It is an arithmetic number, because the mean of its divisors is an integer number (65550615103024).

Almost surely, 2^{131101230206047} is an apocalyptic number.

131101230206047 is a deficient number, since it is larger than the sum of its proper divisors (1).

131101230206047 is an equidigital number, since it uses as much as digits as its factorization.

131101230206047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048, while the sum is 31.

Adding to 131101230206047 its reverse (740602032101131), we get a palindrome (871703262307178).

The spelling of 131101230206047 in words is "one hundred thirty-one trillion, one hundred one billion, two hundred thirty million, two hundred six thousand, forty-seven".