Base | Representation |
---|---|
bin | 11101110011110001100010… |
… | …010011010110101001110101 |
3 | 122012012011012012101111211001 |
4 | 131303301202103112221311 |
5 | 114140430310112440142 |
6 | 1142455023555443301 |
7 | 36420515501501164 |
oct | 3563614223265165 |
9 | 565164165344731 |
10 | 131101230983797 |
11 | 388557a10a75a8 |
12 | 12854368bb6531 |
13 | 581ca403b2629 |
14 | 2453494d3d3db |
15 | 102539d1555b7 |
hex | 773c624d6a75 |
131101230983797 has 2 divisors, whose sum is σ = 131101230983798. Its totient is φ = 131101230983796.
The previous prime is 131101230983771. The next prime is 131101230983813. The reversal of 131101230983797 is 797389032101131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 78057772770961 + 53043458212836 = 8835031^2 + 7283094^2 .
It is a cyclic number.
It is not a de Polignac number, because 131101230983797 - 215 = 131101230951029 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131101230981797) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65550615491898 + 65550615491899.
It is an arithmetic number, because the mean of its divisors is an integer number (65550615491899).
Almost surely, 2131101230983797 is an apocalyptic number.
It is an amenable number.
131101230983797 is a deficient number, since it is larger than the sum of its proper divisors (1).
131101230983797 is an equidigital number, since it uses as much as digits as its factorization.
131101230983797 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1714608, while the sum is 55.
The spelling of 131101230983797 in words is "one hundred thirty-one trillion, one hundred one billion, two hundred thirty million, nine hundred eighty-three thousand, seven hundred ninety-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •