131101253 has 2 divisors, whose sum is σ = 131101254. Its totient is φ = 131101252.

The previous prime is 131101241. The next prime is 131101259. The reversal of 131101253 is 352101131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 125059489 + 6041764 = 11183^2 + 2458^2 .

It is a cyclic number.

It is not a de Polignac number, because 131101253 - 2⁴ = 131101237 is a prime.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131101259) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65550626 + 65550627.

It is an arithmetic number, because the mean of its divisors is an integer number (65550627).

Almost surely, 2^131101253 is an apocalyptic number.

It is an amenable number.

131101253 is a deficient number, since it is larger than the sum of its proper divisors (1).

131101253 is an equidigital number, since it uses as much as digits as its factorization.

131101253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90, while the sum is 17.

The square root of 131101253 is about 11449.9455457220. The cubic root of 131101253 is about 508.0061237301.

Adding to 131101253 its reverse (352101131), we get a palindrome (483202384).

The spelling of 131101253 in words is "one hundred thirty-one million, one hundred one thousand, two hundred fifty-three".