Base | Representation |
---|---|
bin | 10011000100111110011… |
… | …101101101001111011000 |
3 | 11122022221202020211022200 |
4 | 103010332131231033120 |
5 | 132434423312001102 |
6 | 2442134314250200 |
7 | 163501060430502 |
oct | 23047635551730 |
9 | 4568852224280 |
10 | 1311013000152 |
11 | 465aa772a209 |
12 | 1920bb726960 |
13 | 9682192408b |
14 | 4764c080d72 |
15 | 24180bd151c |
hex | 1313e76d3d8 |
1311013000152 has 192 divisors, whose sum is σ = 3720086136000. Its totient is φ = 416309870592.
The previous prime is 1311013000147. The next prime is 1311013000159. The reversal of 1311013000152 is 2510003101131.
1311013000152 is a `hidden beast` number, since 1 + 311 + 0 + 1 + 300 + 0 + 1 + 52 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311013000159) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 649980648 + ... + 649982664.
It is an arithmetic number, because the mean of its divisors is an integer number (19375448625).
Almost surely, 21311013000152 is an apocalyptic number.
1311013000152 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1311013000152, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1860043068000).
1311013000152 is an abundant number, since it is smaller than the sum of its proper divisors (2409073135848).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1311013000152 is a wasteful number, since it uses less digits than its factorization.
1311013000152 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3450 (or 3443 counting only the distinct ones).
The product of its (nonzero) digits is 90, while the sum is 18.
Adding to 1311013000152 its reverse (2510003101131), we get a palindrome (3821016101283).
It can be divided in two parts, 131101 and 3000152, that added together give a triangular number (3131253 = T2502).
The spelling of 1311013000152 in words is "one trillion, three hundred eleven billion, thirteen million, one hundred fifty-two", and thus it is an aban number.
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