Base | Representation |
---|---|
bin | 111101000011000111… |
… | …1110100100001010111 |
3 | 110112101200020202012022 |
4 | 1322012033310201113 |
5 | 4121443414004421 |
6 | 140121020043355 |
7 | 12320545526516 |
oct | 1720617644127 |
9 | 415350222168 |
10 | 131101313111 |
11 | 50666300a5a |
12 | 214a969355b |
13 | c4940c50b2 |
14 | 64b986a67d |
15 | 36248a87ab |
hex | 1e863f4857 |
131101313111 has 2 divisors, whose sum is σ = 131101313112. Its totient is φ = 131101313110.
The previous prime is 131101313089. The next prime is 131101313141. The reversal of 131101313111 is 111313101131.
It is a weak prime.
It is an emirp because it is prime and its reverse (111313101131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131101313111 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 131101313111.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131101313141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65550656555 + 65550656556.
It is an arithmetic number, because the mean of its divisors is an integer number (65550656556).
Almost surely, 2131101313111 is an apocalyptic number.
131101313111 is a deficient number, since it is larger than the sum of its proper divisors (1).
131101313111 is an equidigital number, since it uses as much as digits as its factorization.
131101313111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27, while the sum is 17.
Adding to 131101313111 its reverse (111313101131), we get a palindrome (242414414242).
The spelling of 131101313111 in words is "one hundred thirty-one billion, one hundred one million, three hundred thirteen thousand, one hundred eleven".
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