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13110143320032 = 2531167732538317
BaseRepresentation
bin1011111011000111000101…
…1011110111111111100000
31201102022120102120220202220
42332301301123313333200
53204244033142220112
643514414450111040
72522114400360453
oct276616133677740
951368512526686
1013110143320032
1141a4a8713a310
121578a0057b480
13741386a85875
1433476a27549a
1517b05913e98c
hexbec716f7fe0

13110143320032 has 192 divisors, whose sum is σ = 38624996116224. Its totient is φ = 3859864842240.

The previous prime is 13110143320003. The next prime is 13110143320039. The reversal of 13110143320032 is 23002334101131.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a junction number, because it is equal to n+sod(n) for n = 13110143319984 and 13110143320011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13110143320039) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3895738 + ... + 6434054.

It is an arithmetic number, because the mean of its divisors is an integer number (201171854772).

Almost surely, 213110143320032 is an apocalyptic number.

13110143320032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13110143320032, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19312498058112).

13110143320032 is an abundant number, since it is smaller than the sum of its proper divisors (25514852796192).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13110143320032 is a wasteful number, since it uses less digits than its factorization.

13110143320032 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2538481 (or 2538473 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 13110143320032 its reverse (23002334101131), we get a palindrome (36112477421163).

The spelling of 13110143320032 in words is "thirteen trillion, one hundred ten billion, one hundred forty-three million, three hundred twenty thousand, thirty-two".