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131102001020 = 2256555100051
BaseRepresentation
bin111101000011001001…
…0011100011101111100
3110112101201112200211102
41322012102130131330
54121444103013040
6140121042512232
712320554423214
oct1720622343574
9415351480742
10131102001020
1150666730881
12214a9965678
13c4942a6243
1464b99a9244
153624992515
hex1e8649c77c

131102001020 has 12 divisors (see below), whose sum is σ = 275314202184. Its totient is φ = 52440800400.

The previous prime is 131102001013. The next prime is 131102001031. The reversal of 131102001020 is 20100201131.

It is a junction number, because it is equal to n+sod(n) for n = 131102000992 and 131102001010.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3277550006 + ... + 3277550045.

It is an arithmetic number, because the mean of its divisors is an integer number (22942850182).

Almost surely, 2131102001020 is an apocalyptic number.

131102001020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131102001020 is an abundant number, since it is smaller than the sum of its proper divisors (144212201164).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131102001020 is a wasteful number, since it uses less digits than its factorization.

131102001020 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6555100060 (or 6555100058 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 131102001020 its reverse (20100201131), we get a palindrome (151202202151).

The spelling of 131102001020 in words is "one hundred thirty-one billion, one hundred two million, one thousand, twenty".

Divisors: 1 2 4 5 10 20 6555100051 13110200102 26220400204 32775500255 65551000510 131102001020