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1311020111222 = 2655510055611
BaseRepresentation
bin10011000100111110111…
…000110101010101110110
311122022222020122002212122
4103010332320311111312
5132434432122024342
62442135130515542
7163501205035463
oct23047670652566
94568866562778
101311020111222
11466000746928
12192101b95bb2
1396823243a03
144764cdb266a
15241816384d2
hex1313ee35576

1311020111222 has 4 divisors (see below), whose sum is σ = 1966530166836. Its totient is φ = 655510055610.

The previous prime is 1311020111201. The next prime is 1311020111227. The reversal of 1311020111222 is 2221110201131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a self number, because there is not a number n which added to its sum of digits gives 1311020111222.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311020111227) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 327755027804 + ... + 327755027807.

It is an arithmetic number, because the mean of its divisors is an integer number (491632541709).

Almost surely, 21311020111222 is an apocalyptic number.

1311020111222 is a deficient number, since it is larger than the sum of its proper divisors (655510055614).

1311020111222 is an equidigital number, since it uses as much as digits as its factorization.

1311020111222 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 655510055613.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 1311020111222 its reverse (2221110201131), we get a palindrome (3532130312353).

The spelling of 1311020111222 in words is "one trillion, three hundred eleven billion, twenty million, one hundred eleven thousand, two hundred twenty-two".

Divisors: 1 2 655510055611 1311020111222