Base | Representation |
---|---|
bin | 111101000011001001… |
… | …0100001010110011111 |
3 | 110112101201120201021021 |
4 | 1322012102201112133 |
5 | 4121444104133043 |
6 | 140121043145011 |
7 | 12320554535431 |
oct | 1720622412637 |
9 | 415351521237 |
10 | 131102021023 |
11 | 50666744906 |
12 | 214a9975167 |
13 | c4942b238c |
14 | 64b99b2651 |
15 | 36249983ed |
hex | 1e864a159f |
131102021023 has 2 divisors, whose sum is σ = 131102021024. Its totient is φ = 131102021022.
The previous prime is 131102021003. The next prime is 131102021053. The reversal of 131102021023 is 320120201131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131102021023 - 25 = 131102020991 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131102020988 and 131102021006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131102021003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65551010511 + 65551010512.
It is an arithmetic number, because the mean of its divisors is an integer number (65551010512).
Almost surely, 2131102021023 is an apocalyptic number.
131102021023 is a deficient number, since it is larger than the sum of its proper divisors (1).
131102021023 is an equidigital number, since it uses as much as digits as its factorization.
131102021023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 16.
Adding to 131102021023 its reverse (320120201131), we get a palindrome (451222222154).
The spelling of 131102021023 in words is "one hundred thirty-one billion, one hundred two million, twenty-one thousand, twenty-three".
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