Base | Representation |
---|---|
bin | 10011000100111110111… |
… | …110010001010010110101 |
3 | 11122022222100022111220101 |
4 | 103010332332101102311 |
5 | 132434433003131222 |
6 | 2442135221234101 |
7 | 163501223122564 |
oct | 23047676212265 |
9 | 4568870274811 |
10 | 1311021536437 |
11 | 46600152a698 |
12 | 192102562931 |
13 | 96823622632 |
14 | 4764d263bdb |
15 | 2418181a927 |
hex | 1313ef914b5 |
1311021536437 has 2 divisors, whose sum is σ = 1311021536438. Its totient is φ = 1311021536436.
The previous prime is 1311021536431. The next prime is 1311021536449. The reversal of 1311021536437 is 7346351201131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1239479195761 + 71542340676 = 1113319^2 + 267474^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311021536437 - 231 = 1308874052789 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1311021536396 and 1311021536405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311021536431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655510768218 + 655510768219.
It is an arithmetic number, because the mean of its divisors is an integer number (655510768219).
Almost surely, 21311021536437 is an apocalyptic number.
It is an amenable number.
1311021536437 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311021536437 is an equidigital number, since it uses as much as digits as its factorization.
1311021536437 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45360, while the sum is 37.
Adding to 1311021536437 its reverse (7346351201131), we get a palindrome (8657372737568).
The spelling of 1311021536437 in words is "one trillion, three hundred eleven billion, twenty-one million, five hundred thirty-six thousand, four hundred thirty-seven".
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