13110221147 has 2 divisors, whose sum is σ = 13110221148. Its totient is φ = 13110221146.

The previous prime is 13110221051. The next prime is 13110221149. The reversal of 13110221147 is 74112201131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13110221147 is a prime.

Together with 13110221149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13110221149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555110573 + 6555110574.

It is an arithmetic number, because the mean of its divisors is an integer number (6555110574).

Almost surely, 2^13110221147 is an apocalyptic number.

13110221147 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110221147 is an equidigital number, since it uses as much as digits as its factorization.

13110221147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 336, while the sum is 23.

Adding to 13110221147 its reverse (74112201131), we get a palindrome (87222422278).

The spelling of 13110221147 in words is "thirteen billion, one hundred ten million, two hundred twenty-one thousand, one hundred forty-seven".