Base | Representation |
---|---|
bin | 111101000011001010… |
… | …0000011010001111111 |
3 | 110112101202100002111120 |
4 | 1322012110003101333 |
5 | 4121444210002033 |
6 | 140121055522023 |
7 | 12320561126040 |
oct | 1720624032177 |
9 | 415352302446 |
10 | 131102422143 |
11 | 50666999210 |
12 | 214a9b29313 |
13 | c4943c2b24 |
14 | 64b9a788c7 |
15 | 3624a271b3 |
hex | 1e8650347f |
131102422143 has 64 divisors (see below), whose sum is σ = 221090688000. Its totient is φ = 67120911360.
The previous prime is 131102422103. The next prime is 131102422151. The reversal of 131102422143 is 341224201131.
It is not a de Polignac number, because 131102422143 - 28 = 131102421887 is a prime.
It is a super-2 number, since 2×1311024221432 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131102422103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 32863993 + ... + 32867981.
It is an arithmetic number, because the mean of its divisors is an integer number (3454542000).
Almost surely, 2131102422143 is an apocalyptic number.
131102422143 is a deficient number, since it is larger than the sum of its proper divisors (89988265857).
131102422143 is a wasteful number, since it uses less digits than its factorization.
131102422143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6032.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 131102422143 its reverse (341224201131), we get a palindrome (472326623274).
The spelling of 131102422143 in words is "one hundred thirty-one billion, one hundred two million, four hundred twenty-two thousand, one hundred forty-three".
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