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1311032211157 is a prime number
BaseRepresentation
bin10011000100111111100…
…110111111011011010101
311122100000002101211212101
4103010333212333123111
5132434443221224112
62442140242122101
7163501412632324
oct23047746773325
94570002354771
101311032211157
11466007560779
12192106050331
13968258bc336
14476508420bb
1524182728757
hex1313f9bf6d5

1311032211157 has 2 divisors, whose sum is σ = 1311032211158. Its totient is φ = 1311032211156.

The previous prime is 1311032211043. The next prime is 1311032211199. The reversal of 1311032211157 is 7511122301131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1174624607601 + 136407603556 = 1083801^2 + 369334^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311032211157 - 215 = 1311032178389 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311032211257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655516105578 + 655516105579.

It is an arithmetic number, because the mean of its divisors is an integer number (655516105579).

Almost surely, 21311032211157 is an apocalyptic number.

It is an amenable number.

1311032211157 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311032211157 is an equidigital number, since it uses as much as digits as its factorization.

1311032211157 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1260, while the sum is 28.

Adding to 1311032211157 its reverse (7511122301131), we get a palindrome (8822154512288).

The spelling of 1311032211157 in words is "one trillion, three hundred eleven billion, thirty-two million, two hundred eleven thousand, one hundred fifty-seven".