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13110322198397 is a prime number
BaseRepresentation
bin1011111011000111110000…
…0110001111011101111101
31201102100000220011212202112
42332301330012033131331
53204244414440322042
643514444320103405
72522122001664644
oct276617406173575
951370026155675
1013110322198397
1141a5069106276
121578a50464b65
137413b4b56058
14334785d1a35b
1517b069bc5982
hexbec7c18f77d

13110322198397 has 2 divisors, whose sum is σ = 13110322198398. Its totient is φ = 13110322198396.

The previous prime is 13110322198349. The next prime is 13110322198427. The reversal of 13110322198397 is 79389122301131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7928115807481 + 5182206390916 = 2815691^2 + 2276446^2 .

It is a cyclic number.

It is not a de Polignac number, because 13110322198397 - 236 = 13041602721661 is a prime.

It is a super-2 number, since 2×131103221983972 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13110322197397) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555161099198 + 6555161099199.

It is an arithmetic number, because the mean of its divisors is an integer number (6555161099199).

Almost surely, 213110322198397 is an apocalyptic number.

It is an amenable number.

13110322198397 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110322198397 is an equidigital number, since it uses as much as digits as its factorization.

13110322198397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 489888, while the sum is 50.

The spelling of 13110322198397 in words is "thirteen trillion, one hundred ten billion, three hundred twenty-two million, one hundred ninety-eight thousand, three hundred ninety-seven".