Base | Representation |
---|---|
bin | 111101000011001011… |
… | …1001000110101001011 |
3 | 110112101210212012110121 |
4 | 1322012113020311023 |
5 | 4121444411400212 |
6 | 140121125124111 |
7 | 12320601036106 |
oct | 1720627106513 |
9 | 415353765417 |
10 | 131103231307 |
11 | 506673a1144 |
12 | 214aa259637 |
13 | c494617219 |
14 | 64b9c0973d |
15 | 3624b36d07 |
hex | 1e865c8d4b |
131103231307 has 2 divisors, whose sum is σ = 131103231308. Its totient is φ = 131103231306.
The previous prime is 131103231257. The next prime is 131103231319. The reversal of 131103231307 is 703132301131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131103231307 is a prime.
It is not a weakly prime, because it can be changed into another prime (131103231367) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65551615653 + 65551615654.
It is an arithmetic number, because the mean of its divisors is an integer number (65551615654).
Almost surely, 2131103231307 is an apocalyptic number.
131103231307 is a deficient number, since it is larger than the sum of its proper divisors (1).
131103231307 is an equidigital number, since it uses as much as digits as its factorization.
131103231307 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1134, while the sum is 25.
Adding to 131103231307 its reverse (703132301131), we get a palindrome (834235532438).
The spelling of 131103231307 in words is "one hundred thirty-one billion, one hundred three million, two hundred thirty-one thousand, three hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.111 sec. • engine limits •