Base | Representation |
---|---|
bin | 1011111011000111110010… |
… | …0100110100000000001011 |
3 | 1201102100001110021000212002 |
4 | 2332301330210310000023 |
5 | 3204244424013243423 |
6 | 43514445203541215 |
7 | 2522122130053166 |
oct | 276617444640013 |
9 | 51370043230762 |
10 | 13110330212363 |
11 | 41a507268a28a |
12 | 1578a5308a80b |
13 | 7413b6700947 |
14 | 334787004add |
15 | 17b06a75a228 |
hex | bec7c93400b |
13110330212363 has 2 divisors, whose sum is σ = 13110330212364. Its totient is φ = 13110330212362.
The previous prime is 13110330212359. The next prime is 13110330212431. The reversal of 13110330212363 is 36321203301131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13110330212363 - 22 = 13110330212359 is a prime.
It is a super-3 number, since 3×131103302123633 (a number of 40 digits) contains 333 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (13110330212323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555165106181 + 6555165106182.
It is an arithmetic number, because the mean of its divisors is an integer number (6555165106182).
Almost surely, 213110330212363 is an apocalyptic number.
13110330212363 is a deficient number, since it is larger than the sum of its proper divisors (1).
13110330212363 is an equidigital number, since it uses as much as digits as its factorization.
13110330212363 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5832, while the sum is 29.
Adding to 13110330212363 its reverse (36321203301131), we get a palindrome (49431533513494).
The spelling of 13110330212363 in words is "thirteen trillion, one hundred ten billion, three hundred thirty million, two hundred twelve thousand, three hundred sixty-three".
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