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13110330212431 is a prime number
BaseRepresentation
bin1011111011000111110010…
…0100110100000001001111
31201102100001110021000221121
42332301330210310001033
53204244424013244211
643514445203541411
72522122130053324
oct276617444640117
951370043230847
1013110330212431
1141a507268a341
121578a5308a867
137413b670099a
14334787004b4b
1517b06a75a271
hexbec7c93404f

13110330212431 has 2 divisors, whose sum is σ = 13110330212432. Its totient is φ = 13110330212430.

The previous prime is 13110330212363. The next prime is 13110330212453. The reversal of 13110330212431 is 13421203301131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13110330212431 - 227 = 13110195994703 is a prime.

It is a super-2 number, since 2×131103302124312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13110330212396 and 13110330212405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13110330210431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555165106215 + 6555165106216.

It is an arithmetic number, because the mean of its divisors is an integer number (6555165106216).

Almost surely, 213110330212431 is an apocalyptic number.

13110330212431 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110330212431 is an equidigital number, since it uses as much as digits as its factorization.

13110330212431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 13110330212431 its reverse (13421203301131), we get a palindrome (26531533513562).

The spelling of 13110330212431 in words is "thirteen trillion, one hundred ten billion, three hundred thirty million, two hundred twelve thousand, four hundred thirty-one".