Base | Representation |
---|---|
bin | 111101000011001011… |
… | …1100001000001100001 |
3 | 110112101211001020101202 |
4 | 1322012113201001201 |
5 | 4121444423033101 |
6 | 140121131210545 |
7 | 12320601631031 |
oct | 1720627410141 |
9 | 415354036352 |
10 | 131103330401 |
11 | 5066745963a |
12 | 214aa2a6a55 |
13 | c494650364 |
14 | 64b9c338c1 |
15 | 3624b5636b |
hex | 1e865e1061 |
131103330401 has 2 divisors, whose sum is σ = 131103330402. Its totient is φ = 131103330400.
The previous prime is 131103330317. The next prime is 131103330403. The reversal of 131103330401 is 104033301131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 91022890000 + 40080440401 = 301700^2 + 200201^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131103330401 is a prime.
Together with 131103330403, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (131103330403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65551665200 + 65551665201.
It is an arithmetic number, because the mean of its divisors is an integer number (65551665201).
Almost surely, 2131103330401 is an apocalyptic number.
It is an amenable number.
131103330401 is a deficient number, since it is larger than the sum of its proper divisors (1).
131103330401 is an equidigital number, since it uses as much as digits as its factorization.
131103330401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 131103330401 its reverse (104033301131), we get a palindrome (235136631532).
The spelling of 131103330401 in words is "one hundred thirty-one billion, one hundred three million, three hundred thirty thousand, four hundred one".
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