13110341407 has 4 divisors (see below), whose sum is σ = 13129537320. Its totient is φ = 13091145496.

The previous prime is 13110341399. The next prime is 13110341459. The reversal of 13110341407 is 70414301131.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 70414301131 = 19 ⋅3706015849.

It is a cyclic number.

It is not a de Polignac number, because 13110341407 - 2³ = 13110341399 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13110341477) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9596932 + ... + 9598297.

It is an arithmetic number, because the mean of its divisors is an integer number (3282384330).

Almost surely, 2^13110341407 is an apocalyptic number.

13110341407 is a deficient number, since it is larger than the sum of its proper divisors (19195913).

13110341407 is an equidigital number, since it uses as much as digits as its factorization.

13110341407 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19195912.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 13110341407 its reverse (70414301131), we get a palindrome (83524642538).

The spelling of 13110341407 in words is "thirteen billion, one hundred ten million, three hundred forty-one thousand, four hundred seven".