Base | Representation |
---|---|
bin | 1011111011000111111000… |
… | …0101100001100111001011 |
3 | 1201102100010012222002010202 |
4 | 2332301332011201213023 |
5 | 3204300002011040003 |
6 | 43514451511202415 |
7 | 2522122555414454 |
oct | 276617605414713 |
9 | 51370105862122 |
10 | 13110355565003 |
11 | 41a5085a26084 |
12 | 1578a5b67640b |
13 | 7413bba394c8 |
14 | 33478a52412b |
15 | 17b06cab7088 |
hex | bec7e1619cb |
13110355565003 has 2 divisors, whose sum is σ = 13110355565004. Its totient is φ = 13110355565002.
The previous prime is 13110355564973. The next prime is 13110355565023. The reversal of 13110355565003 is 30056555301131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13110355565003 is a prime.
It is not a weakly prime, because it can be changed into another prime (13110355565023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555177782501 + 6555177782502.
It is an arithmetic number, because the mean of its divisors is an integer number (6555177782502).
Almost surely, 213110355565003 is an apocalyptic number.
13110355565003 is a deficient number, since it is larger than the sum of its proper divisors (1).
13110355565003 is an equidigital number, since it uses as much as digits as its factorization.
13110355565003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 101250, while the sum is 38.
The spelling of 13110355565003 in words is "thirteen trillion, one hundred ten billion, three hundred fifty-five million, five hundred sixty-five thousand, three".
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