Base | Representation |
---|---|
bin | 1011111011001000000011… |
… | …1110010111011110110000 |
3 | 1201102100020121010212002121 |
4 | 2332302000332113132300 |
5 | 3204300101412121034 |
6 | 43514500401524024 |
7 | 2522124014316214 |
oct | 276620076273660 |
9 | 51370217125077 |
10 | 13110404020144 |
11 | 41a5100311152 |
12 | 1578a73943614 |
13 | 7413c8aa36a2 |
14 | 334792b38944 |
15 | 17b071e891b4 |
hex | bec80f977b0 |
13110404020144 has 10 divisors (see below), whose sum is σ = 25401407789060. Its totient is φ = 6555202010064.
The previous prime is 13110404020141. The next prime is 13110404020213. The reversal of 13110404020144 is 44102040401131.
It is not an unprimeable number, because it can be changed into a prime (13110404020141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 409700125614 + ... + 409700125645.
It is an arithmetic number, because the mean of its divisors is an integer number (2540140778906).
Almost surely, 213110404020144 is an apocalyptic number.
It is an amenable number.
13110404020144 is a deficient number, since it is larger than the sum of its proper divisors (12291003768916).
13110404020144 is an equidigital number, since it uses as much as digits as its factorization.
13110404020144 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 819400251267 (or 819400251261 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 13110404020144 its reverse (44102040401131), we get a palindrome (57212444421275).
The spelling of 13110404020144 in words is "thirteen trillion, one hundred ten billion, four hundred four million, twenty thousand, one hundred forty-four".
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