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1311043544513 is a prime number
BaseRepresentation
bin10011000101000000010…
…010001110010111000001
311122100000212201122022022
4103011000102032113001
5132440004121411023
62442141325051225
7163501611154223
oct23050022162701
94570025648268
101311043544513
114660129a168a
121921099b6b15
1396828059a71
1447652152413
15241837167c8
hex1314048e5c1

1311043544513 has 2 divisors, whose sum is σ = 1311043544514. Its totient is φ = 1311043544512.

The previous prime is 1311043544479. The next prime is 1311043544557. The reversal of 1311043544513 is 3154453401131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1090339021249 + 220704523264 = 1044193^2 + 469792^2 .

It is an emirp because it is prime and its reverse (3154453401131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1311043544513 is a prime.

It is a super-2 number, since 2×13110435445132 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1311043544563) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655521772256 + 655521772257.

It is an arithmetic number, because the mean of its divisors is an integer number (655521772257).

Almost surely, 21311043544513 is an apocalyptic number.

It is an amenable number.

1311043544513 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311043544513 is an equidigital number, since it uses as much as digits as its factorization.

1311043544513 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43200, while the sum is 35.

Adding to 1311043544513 its reverse (3154453401131), we get a palindrome (4465496945644).

The spelling of 1311043544513 in words is "one trillion, three hundred eleven billion, forty-three million, five hundred forty-four thousand, five hundred thirteen".