Base | Representation |
---|---|
bin | 111101000011001101… |
… | …1100111001111101111 |
3 | 110112101220001210201211 |
4 | 1322012123213033233 |
5 | 4122000211420323 |
6 | 140121210215251 |
7 | 12320614023304 |
oct | 1720633471757 |
9 | 415356053654 |
10 | 131104404463 |
11 | 5066802259a |
12 | 214aa724527 |
13 | c4949381b6 |
14 | 64ba0330ab |
15 | 3624cb970d |
hex | 1e866e73ef |
131104404463 has 2 divisors, whose sum is σ = 131104404464. Its totient is φ = 131104404462.
The previous prime is 131104404451. The next prime is 131104404467. The reversal of 131104404463 is 364404401131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131104404463 - 233 = 122514469871 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131104404467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65552202231 + 65552202232.
It is an arithmetic number, because the mean of its divisors is an integer number (65552202232).
Almost surely, 2131104404463 is an apocalyptic number.
131104404463 is a deficient number, since it is larger than the sum of its proper divisors (1).
131104404463 is an equidigital number, since it uses as much as digits as its factorization.
131104404463 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 131104404463 its reverse (364404401131), we get a palindrome (495508805594).
The spelling of 131104404463 in words is "one hundred thirty-one billion, one hundred four million, four hundred four thousand, four hundred sixty-three".
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