Base | Representation |
---|---|
bin | 1011111011001000001101… |
… | …0011111110101001110110 |
3 | 1201102100100022221102200212 |
4 | 2332302003103332221312 |
5 | 3204300141432140204 |
6 | 43514504322305422 |
7 | 2522125001555036 |
oct | 276620323765166 |
9 | 51370308842625 |
10 | 13110443240054 |
11 | 41a51204696a6 |
12 | 1578a84ab8272 |
13 | 741403c56134 |
14 | 3347980278c6 |
15 | 17b075634c6e |
hex | bec834fea76 |
13110443240054 has 8 divisors (see below), whose sum is σ = 20145315222648. Its totient is φ = 6395338165840.
The previous prime is 13110443240051. The next prime is 13110443240087. The reversal of 13110443240054 is 45004234401131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 13110443240054.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13110443240051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79941726992 + ... + 79941727155.
It is an arithmetic number, because the mean of its divisors is an integer number (2518164402831).
Almost surely, 213110443240054 is an apocalyptic number.
13110443240054 is a deficient number, since it is larger than the sum of its proper divisors (7034871982594).
13110443240054 is a wasteful number, since it uses less digits than its factorization.
13110443240054 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 159883454190.
The product of its (nonzero) digits is 23040, while the sum is 32.
Adding to 13110443240054 its reverse (45004234401131), we get a palindrome (58114677641185).
The spelling of 13110443240054 in words is "thirteen trillion, one hundred ten billion, four hundred forty-three million, two hundred forty thousand, fifty-four".
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