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13110450104201 is a prime number
BaseRepresentation
bin1011111011001000001110…
…1110001010011110001001
31201102100100210212011112112
42332302003232022132021
53204300200211313301
643514505125352105
72522125114114112
oct276620356123611
951370323764475
1013110450104201
1141a512432784a
121578a87268635
137414054ba568
14334798cd3209
1517b07603d9bb
hexbec83b8a789

13110450104201 has 2 divisors, whose sum is σ = 13110450104202. Its totient is φ = 13110450104200.

The previous prime is 13110450104197. The next prime is 13110450104203. The reversal of 13110450104201 is 10240105401131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12698703298576 + 411746805625 = 3563524^2 + 641675^2 .

It is a cyclic number.

It is not a de Polignac number, because 13110450104201 - 22 = 13110450104197 is a prime.

Together with 13110450104203, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13110450104203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555225052100 + 6555225052101.

It is an arithmetic number, because the mean of its divisors is an integer number (6555225052101).

Almost surely, 213110450104201 is an apocalyptic number.

It is an amenable number.

13110450104201 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110450104201 is an equidigital number, since it uses as much as digits as its factorization.

13110450104201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 480, while the sum is 23.

Adding to 13110450104201 its reverse (10240105401131), we get a palindrome (23350555505332).

The spelling of 13110450104201 in words is "thirteen trillion, one hundred ten billion, four hundred fifty million, one hundred four thousand, two hundred one".