Base | Representation |
---|---|
bin | 10011000101000001010… |
… | …101110001111110100101 |
3 | 11122100002010001101020012 |
4 | 103011001111301332211 |
5 | 132440023140112203 |
6 | 2442143200420005 |
7 | 163502214533435 |
oct | 23050125617645 |
9 | 4570063041205 |
10 | 1311061254053 |
11 | 466021998071 |
12 | 192113917605 |
13 | 9682b91a795 |
14 | 476546422c5 |
15 | 24185063bd8 |
hex | 13141571fa5 |
1311061254053 has 8 divisors (see below), whose sum is σ = 1343721156480. Its totient is φ = 1278599892640.
The previous prime is 1311061253989. The next prime is 1311061254071. The reversal of 1311061254053 is 3504521601131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1311061254053 - 26 = 1311061253989 is a prime.
It is a super-2 number, since 2×13110612540532 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311061254953) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 49621883 + ... + 49648296.
It is an arithmetic number, because the mean of its divisors is an integer number (167965144560).
Almost surely, 21311061254053 is an apocalyptic number.
It is an amenable number.
1311061254053 is a deficient number, since it is larger than the sum of its proper divisors (32659902427).
1311061254053 is an equidigital number, since it uses as much as digits as its factorization.
1311061254053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 99270507.
The product of its (nonzero) digits is 10800, while the sum is 32.
Adding to 1311061254053 its reverse (3504521601131), we get a palindrome (4815582855184).
The spelling of 1311061254053 in words is "one trillion, three hundred eleven billion, sixty-one million, two hundred fifty-four thousand, fifty-three".
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