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1311100011014 = 2655550005507
BaseRepresentation
bin10011000101000011101…
…001101000001000000110
311122100011210222102210012
4103011003221220020012
5132440113100323024
62442151103230222
7163503165133463
oct23050351501006
94570153872705
101311100011014
11466041859812
121921248a8372
139683696a5b1
144765985066a
152418866c50e
hex13143a68206

1311100011014 has 4 divisors (see below), whose sum is σ = 1966650016524. Its totient is φ = 655550005506.

The previous prime is 1311100010999. The next prime is 1311100011029. The reversal of 1311100011014 is 4101100011131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1311100010999) and next prime (1311100011029).

It is a self number, because there is not a number n which added to its sum of digits gives 1311100011014.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 327775002752 + ... + 327775002755.

It is an arithmetic number, because the mean of its divisors is an integer number (491662504131).

Almost surely, 21311100011014 is an apocalyptic number.

1311100011014 is a deficient number, since it is larger than the sum of its proper divisors (655550005510).

1311100011014 is an equidigital number, since it uses as much as digits as its factorization.

1311100011014 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 655550005509.

The product of its (nonzero) digits is 12, while the sum is 14.

Adding to 1311100011014 its reverse (4101100011131), we get a palindrome (5412200022145).

The spelling of 1311100011014 in words is "one trillion, three hundred eleven billion, one hundred million, eleven thousand, fourteen".

Divisors: 1 2 655550005507 1311100011014