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131110097017 is a prime number
BaseRepresentation
bin111101000011011000…
…1010101000001111001
3110112102021210000110011
41322012301111001321
54122003141101032
6140121532221521
712321013302544
oct1720661250171
9415367700404
10131110097017
1150670260489
12214b060a8a1
13c495b7c283
1464baab585b
153625541247
hex1e86c55079

131110097017 has 2 divisors, whose sum is σ = 131110097018. Its totient is φ = 131110097016.

The previous prime is 131110097011. The next prime is 131110097029. The reversal of 131110097017 is 710790011131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 91820514361 + 39289582656 = 303019^2 + 198216^2 .

It is a cyclic number.

It is not a de Polignac number, because 131110097017 - 215 = 131110064249 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131110097017.

It is not a weakly prime, because it can be changed into another prime (131110097011) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65555048508 + 65555048509.

It is an arithmetic number, because the mean of its divisors is an integer number (65555048509).

Almost surely, 2131110097017 is an apocalyptic number.

It is an amenable number.

131110097017 is a deficient number, since it is larger than the sum of its proper divisors (1).

131110097017 is an equidigital number, since it uses as much as digits as its factorization.

131110097017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1323, while the sum is 31.

The spelling of 131110097017 in words is "one hundred thirty-one billion, one hundred ten million, ninety-seven thousand, seventeen".