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131110100293 is a prime number
BaseRepresentation
bin111101000011011000…
…1010101110101000101
3110112102021210011221111
41322012301111311011
54122003141202133
6140121532245021
712321013315234
oct1720661256505
9415367704844
10131110100293
1150670262997
12214b0610771
13c495b80903
1464baab6b1b
1536255421cd
hex1e86c55d45

131110100293 has 2 divisors, whose sum is σ = 131110100294. Its totient is φ = 131110100292.

The previous prime is 131110100279. The next prime is 131110100299. The reversal of 131110100293 is 392001011131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 105766097089 + 25344003204 = 325217^2 + 159198^2 .

It is an emirp because it is prime and its reverse (392001011131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131110100293 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131110100299) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65555050146 + 65555050147.

It is an arithmetic number, because the mean of its divisors is an integer number (65555050147).

Almost surely, 2131110100293 is an apocalyptic number.

It is an amenable number.

131110100293 is a deficient number, since it is larger than the sum of its proper divisors (1).

131110100293 is an equidigital number, since it uses as much as digits as its factorization.

131110100293 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 22.

The spelling of 131110100293 in words is "one hundred thirty-one billion, one hundred ten million, one hundred thousand, two hundred ninety-three".