Base | Representation |
---|---|
bin | 11000011010111101… |
… | …00010001110011001 |
3 | 1020211201200022211102 |
4 | 30031132202032121 |
5 | 203322404311301 |
6 | 10004554241145 |
7 | 642621514352 |
oct | 141536421631 |
9 | 36751608742 |
10 | 13111010201 |
11 | 5618907023 |
12 | 265aa261b5 |
13 | 130c39bb03 |
14 | 8c53c4d29 |
15 | 51b07db6b |
hex | 30d7a2399 |
13111010201 has 2 divisors, whose sum is σ = 13111010202. Its totient is φ = 13111010200.
The previous prime is 13111010153. The next prime is 13111010233. The reversal of 13111010201 is 10201011131.
It is a happy number.
13111010201 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9056377225 + 4054632976 = 95165^2 + 63676^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13111010201 is a prime.
It is not a weakly prime, because it can be changed into another prime (13111010251) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555505100 + 6555505101.
It is an arithmetic number, because the mean of its divisors is an integer number (6555505101).
Almost surely, 213111010201 is an apocalyptic number.
It is an amenable number.
13111010201 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111010201 is an equidigital number, since it uses as much as digits as its factorization.
13111010201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6, while the sum is 11.
Adding to 13111010201 its reverse (10201011131), we get a palindrome (23312021332).
The spelling of 13111010201 in words is "thirteen billion, one hundred eleven million, ten thousand, two hundred one".
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