Base | Representation |
---|---|
bin | 10011000101000011101… |
… | …110010010000100110101 |
3 | 11122100011220021102212011 |
4 | 103011003232102010311 |
5 | 132440113403401123 |
6 | 2442151145324221 |
7 | 163503211405501 |
oct | 23050356220465 |
9 | 4570156242764 |
10 | 1311101231413 |
11 | 466042512706 |
12 | 192125196671 |
13 | 96836ca6c1c |
14 | 47659a8b301 |
15 | 2418880de0d |
hex | 13143b92135 |
1311101231413 has 2 divisors, whose sum is σ = 1311101231414. Its totient is φ = 1311101231412.
The previous prime is 1311101231389. The next prime is 1311101231483. The reversal of 1311101231413 is 3141321011131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1278125213764 + 32976017649 = 1130542^2 + 181593^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311101231413 - 213 = 1311101223221 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311101231483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655550615706 + 655550615707.
It is an arithmetic number, because the mean of its divisors is an integer number (655550615707).
Almost surely, 21311101231413 is an apocalyptic number.
It is an amenable number.
1311101231413 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311101231413 is an equidigital number, since it uses as much as digits as its factorization.
1311101231413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 22.
Adding to 1311101231413 its reverse (3141321011131), we get a palindrome (4452422242544).
The spelling of 1311101231413 in words is "one trillion, three hundred eleven billion, one hundred one million, two hundred thirty-one thousand, four hundred thirteen".
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