1311102061177 has 2 divisors, whose sum is σ = 1311102061178. Its totient is φ = 1311102061176.

The previous prime is 1311102061133. The next prime is 1311102061201. The reversal of 1311102061177 is 7711602011131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 800328841321 + 510773219856 = 894611^2 + 714684^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1311102061177 is a prime.

It is a super-2 number, since 2×1311102061177² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1311102061777) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655551030588 + 655551030589.

It is an arithmetic number, because the mean of its divisors is an integer number (655551030589).

Almost surely, 2^{1311102061177} is an apocalyptic number.

It is an amenable number.

1311102061177 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311102061177 is an equidigital number, since it uses as much as digits as its factorization.

1311102061177 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1764, while the sum is 31.

The spelling of 1311102061177 in words is "one trillion, three hundred eleven billion, one hundred two million, sixty-one thousand, one hundred seventy-seven".