1311102061133 has 2 divisors, whose sum is σ = 1311102061134. Its totient is φ = 1311102061132.

The previous prime is 1311102061109. The next prime is 1311102061177. The reversal of 1311102061133 is 3311602011131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1077583096489 + 233518964644 = 1038067^2 + 483238^2 .

It is an emirp because it is prime and its reverse (3311602011131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1311102061133 - 2¹⁶ = 1311101995597 is a prime.

It is a super-2 number, since 2×1311102061133² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1311102061099 and 1311102061108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311102063133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655551030566 + 655551030567.

It is an arithmetic number, because the mean of its divisors is an integer number (655551030567).

Almost surely, 2^{1311102061133} is an apocalyptic number.

It is an amenable number.

1311102061133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311102061133 is an equidigital number, since it uses as much as digits as its factorization.

1311102061133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324, while the sum is 23.

Adding to 1311102061133 its reverse (3311602011131), we get a palindrome (4622704072264).

The spelling of 1311102061133 in words is "one trillion, three hundred eleven billion, one hundred two million, sixty-one thousand, one hundred thirty-three".