Base | Representation |
---|---|
bin | 11101110011111010000000… |
… | …000011001100110000001101 |
3 | 122012020000122121222101010021 |
4 | 131303322000003030300031 |
5 | 114141102413410000023 |
6 | 1142503125520542141 |
7 | 36421256645036554 |
oct | 3563720003146015 |
9 | 565200577871107 |
10 | 131110320000013 |
11 | 38859635667a52 |
12 | 12856084a81951 |
13 | 582085b42bb33 |
14 | 2453ab80c6d9b |
15 | 102573106735d |
hex | 773e800ccc0d |
131110320000013 has 2 divisors, whose sum is σ = 131110320000014. Its totient is φ = 131110320000012.
The previous prime is 131110319999977. The next prime is 131110320000067. The reversal of 131110320000013 is 310000023011131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 129283881274249 + 1826438725764 = 11370307^2 + 1351458^2 .
It is a cyclic number.
It is not a de Polignac number, because 131110320000013 - 29 = 131110319999501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131110320000073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65555160000006 + 65555160000007.
It is an arithmetic number, because the mean of its divisors is an integer number (65555160000007).
Almost surely, 2131110320000013 is an apocalyptic number.
It is an amenable number.
131110320000013 is a deficient number, since it is larger than the sum of its proper divisors (1).
131110320000013 is an equidigital number, since it uses as much as digits as its factorization.
131110320000013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 131110320000013 its reverse (310000023011131), we get a palindrome (441110343011144).
The spelling of 131110320000013 in words is "one hundred thirty-one trillion, one hundred ten billion, three hundred twenty million, thirteen", and thus it is an aban number.
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