13111103404039 has 2 divisors, whose sum is σ = 13111103404040. Its totient is φ = 13111103404038.

The previous prime is 13111103403991. The next prime is 13111103404111. The reversal of 13111103404039 is 93040430111131.

13111103404039 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13111103404039 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13111103404039.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13111103402039) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555551702019 + 6555551702020.

It is an arithmetic number, because the mean of its divisors is an integer number (6555551702020).

Almost surely, 2^{13111103404039} is an apocalyptic number.

13111103404039 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111103404039 is an equidigital number, since it uses as much as digits as its factorization.

13111103404039 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 31.

The spelling of 13111103404039 in words is "thirteen trillion, one hundred eleven billion, one hundred three million, four hundred four thousand, thirty-nine".