13111110012059 has 2 divisors, whose sum is σ = 13111110012060. Its totient is φ = 13111110012058.

The previous prime is 13111110011927. The next prime is 13111110012061. The reversal of 13111110012059 is 95021001111131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13111110012059 - 2⁴⁰ = 12011598384283 is a prime.

It is a super-2 number, since 2×13111110012059² (a number of 27 digits) contains 22 as substring.

Together with 13111110012061, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13111110011059) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555555006029 + 6555555006030.

It is an arithmetic number, because the mean of its divisors is an integer number (6555555006030).

Almost surely, 2^{13111110012059} is an apocalyptic number.

13111110012059 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111110012059 is an equidigital number, since it uses as much as digits as its factorization.

13111110012059 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 270, while the sum is 26.

The spelling of 13111110012059 in words is "thirteen trillion, one hundred eleven billion, one hundred ten million, twelve thousand, fifty-nine".