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13111211300849 is a prime number
BaseRepresentation
bin1011111011001011000100…
…0101111001011111110001
31201102102022212011222000222
42332302301011321133301
53204303230043111344
643515112440422425
72522153016145244
oct276626105713761
951372285158028
1013111211300849
1141a5484a75092
12157905a177a15
137414c710548c
1433482c03b25b
1517b0bcc9d5ee
hexbecb11797f1

13111211300849 has 2 divisors, whose sum is σ = 13111211300850. Its totient is φ = 13111211300848.

The previous prime is 13111211300813. The next prime is 13111211300909. The reversal of 13111211300849 is 94800311211131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9518878631824 + 3592332669025 = 3085268^2 + 1895345^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13111211300849 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (13111211300249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555605650424 + 6555605650425.

It is an arithmetic number, because the mean of its divisors is an integer number (6555605650425).

Almost surely, 213111211300849 is an apocalyptic number.

It is an amenable number.

13111211300849 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111211300849 is an equidigital number, since it uses as much as digits as its factorization.

13111211300849 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 35.

The spelling of 13111211300849 in words is "thirteen trillion, one hundred eleven billion, two hundred eleven million, three hundred thousand, eight hundred forty-nine".