13111211300249 has 2 divisors, whose sum is σ = 13111211300250. Its totient is φ = 13111211300248.

The previous prime is 13111211300167. The next prime is 13111211300281. The reversal of 13111211300249 is 94200311211131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11455246393600 + 1655964906649 = 3384560^2 + 1286843^2 .

It is an emirp because it is prime and its reverse (94200311211131) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13111211300249 is a prime.

It is not a weakly prime, because it can be changed into another prime (13111211300849) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555605650124 + 6555605650125.

It is an arithmetic number, because the mean of its divisors is an integer number (6555605650125).

Almost surely, 2^{13111211300249} is an apocalyptic number.

It is an amenable number.

13111211300249 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111211300249 is an equidigital number, since it uses as much as digits as its factorization.

13111211300249 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 29.

The spelling of 13111211300249 in words is "thirteen trillion, one hundred eleven billion, two hundred eleven million, three hundred thousand, two hundred forty-nine".