Search a number
-
+
131112153553 is a prime number
BaseRepresentation
bin111101000011011100…
…1001011000111010001
3110112102102122111111011
41322012321023013101
54122004202403203
6140122044250521
712321036626353
oct1720671130721
9415372574434
10131112153553
11506714355a7
12214b1240a41
13c49641c364
1464bb08d0d3
1536257ea76d
hex1e86e4b1d1

131112153553 has 2 divisors, whose sum is σ = 131112153554. Its totient is φ = 131112153552.

The previous prime is 131112153551. The next prime is 131112153577. The reversal of 131112153553 is 355351211131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 122764042129 + 8348111424 = 350377^2 + 91368^2 .

It is a cyclic number.

It is not a de Polignac number, because 131112153553 - 21 = 131112153551 is a prime.

Together with 131112153551, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (131112153551) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65556076776 + 65556076777.

It is an arithmetic number, because the mean of its divisors is an integer number (65556076777).

Almost surely, 2131112153553 is an apocalyptic number.

It is an amenable number.

131112153553 is a deficient number, since it is larger than the sum of its proper divisors (1).

131112153553 is an equidigital number, since it uses as much as digits as its factorization.

131112153553 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6750, while the sum is 31.

Adding to 131112153553 its reverse (355351211131), we get a palindrome (486463364684).

The spelling of 131112153553 in words is "one hundred thirty-one billion, one hundred twelve million, one hundred fifty-three thousand, five hundred fifty-three".