Base | Representation |
---|---|
bin | 11101110011111011110010… |
… | …100001000100110010011010 |
3 | 122012020012121110121112202012 |
4 | 131303323302201010302122 |
5 | 114141120332022344310 |
6 | 1142504044242305522 |
7 | 36421355354334461 |
oct | 3563736241046232 |
9 | 565205543545665 |
10 | 131112240434330 |
11 | 3885a4306aa751 |
12 | 128565200582a2 |
13 | 5820aa62686bc |
14 | 2453c1b18d9d8 |
15 | 10257e495ec05 |
hex | 773ef2844c9a |
131112240434330 has 8 divisors (see below), whose sum is σ = 236002032781812. Its totient is φ = 52444896173728.
The previous prime is 131112240434323. The next prime is 131112240434479. The reversal of 131112240434330 is 33434042211131.
It can be written as a sum of positive squares in 2 ways, for example, as 107692360965049 + 23419879469281 = 10377493^2 + 4839409^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6555612021707 + ... + 6555612021726.
Almost surely, 2131112240434330 is an apocalyptic number.
131112240434330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131112240434330 is a deficient number, since it is larger than the sum of its proper divisors (104889792347482).
131112240434330 is a wasteful number, since it uses less digits than its factorization.
131112240434330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13111224043440.
The product of its (nonzero) digits is 20736, while the sum is 32.
Adding to 131112240434330 its reverse (33434042211131), we get a palindrome (164546282645461).
The spelling of 131112240434330 in words is "one hundred thirty-one trillion, one hundred twelve billion, two hundred forty million, four hundred thirty-four thousand, three hundred thirty".
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