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131112298950109 is a prime number
BaseRepresentation
bin11101110011111011110110…
…000000010010110111011101
3122012020012202112201110022021
4131303323312000102313131
5114141120442012400414
61142504054132420141
736421356664610431
oct3563736600226735
9565205675643267
10131112298950109
113885a4607374a4
1212856537777651
135820ab5415c19
142453c24c629c1
1510257e9b6cc24
hex773ef6012ddd

131112298950109 has 2 divisors, whose sum is σ = 131112298950110. Its totient is φ = 131112298950108.

The previous prime is 131112298949987. The next prime is 131112298950151. The reversal of 131112298950109 is 901059892211131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 127715200243225 + 3397098706884 = 11301115^2 + 1843122^2 .

It is a cyclic number.

It is not a de Polignac number, because 131112298950109 - 217 = 131112298819037 is a prime.

It is a super-3 number, since 3×1311122989501093 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131112298950179) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65556149475054 + 65556149475055.

It is an arithmetic number, because the mean of its divisors is an integer number (65556149475055).

Almost surely, 2131112298950109 is an apocalyptic number.

It is an amenable number.

131112298950109 is a deficient number, since it is larger than the sum of its proper divisors (1).

131112298950109 is an equidigital number, since it uses as much as digits as its factorization.

131112298950109 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 349920, while the sum is 52.

The spelling of 131112298950109 in words is "one hundred thirty-one trillion, one hundred twelve billion, two hundred ninety-eight million, nine hundred fifty thousand, one hundred nine".