Base | Representation |
---|---|
bin | 1011111011001011001001… |
… | …0001011100000001110101 |
3 | 1201102102101020110000121102 |
4 | 2332302302101130001311 |
5 | 3204303300130244333 |
6 | 43515114425055445 |
7 | 2522153346361604 |
oct | 276626221340165 |
9 | 51372336400542 |
10 | 13111231103093 |
11 | 41a549516a882 |
12 | 1579064927585 |
13 | 7414cb249896 |
14 | 334830913a3b |
15 | 17b0be8b0ae8 |
hex | becb245c075 |
13111231103093 has 2 divisors, whose sum is σ = 13111231103094. Its totient is φ = 13111231103092.
The previous prime is 13111231103077. The next prime is 13111231103207. The reversal of 13111231103093 is 39030113211131.
13111231103093 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8953967013124 + 4157264089969 = 2992318^2 + 2038937^2 .
It is a cyclic number.
It is not a de Polignac number, because 13111231103093 - 24 = 13111231103077 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13111231153093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555615551546 + 6555615551547.
It is an arithmetic number, because the mean of its divisors is an integer number (6555615551547).
Almost surely, 213111231103093 is an apocalyptic number.
It is an amenable number.
13111231103093 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111231103093 is an equidigital number, since it uses as much as digits as its factorization.
13111231103093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1458, while the sum is 29.
The spelling of 13111231103093 in words is "thirteen trillion, one hundred eleven billion, two hundred thirty-one million, one hundred three thousand, ninety-three".
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