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13111231212119 is a prime number
BaseRepresentation
bin1011111011001011001001…
…0001110110101001010111
31201102102101020122120011102
42332302302101312221113
53204303300142241434
643515114431300315
72522153350324505
oct276626221665127
951372336576142
1013111231212119
1141a5495234787
12157906497a69b
137414cb2873b1
14334830941675
1517b0be8d307e
hexbecb2476a57

13111231212119 has 2 divisors, whose sum is σ = 13111231212120. Its totient is φ = 13111231212118.

The previous prime is 13111231212113. The next prime is 13111231212139. The reversal of 13111231212119 is 91121213211131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13111231212119 - 216 = 13111231146583 is a prime.

It is a super-2 number, since 2×131112312121192 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13111231212091 and 13111231212100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13111231212113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555615606059 + 6555615606060.

It is an arithmetic number, because the mean of its divisors is an integer number (6555615606060).

Almost surely, 213111231212119 is an apocalyptic number.

13111231212119 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111231212119 is an equidigital number, since it uses as much as digits as its factorization.

13111231212119 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 648, while the sum is 29.

The spelling of 13111231212119 in words is "thirteen trillion, one hundred eleven billion, two hundred thirty-one million, two hundred twelve thousand, one hundred nineteen".