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131112649 is a prime number
BaseRepresentation
bin1111101000010…
…01111011001001
3100010201012202001
413310021323021
5232031101044
621002111001
73151303423
oct764117311
9303635661
10131112649
1168011968
1237aab461
1321218065
14135ad813
15b79d2d4
hex7d09ec9

131112649 has 2 divisors, whose sum is σ = 131112650. Its totient is φ = 131112648.

The previous prime is 131112637. The next prime is 131112661. The reversal of 131112649 is 946211131.

It is a balanced prime because it is at equal distance from previous prime (131112637) and next prime (131112661).

It can be written as a sum of positive squares in only one way, i.e., 76825225 + 54287424 = 8765^2 + 7368^2 .

It is a cyclic number.

It is not a de Polignac number, because 131112649 - 25 = 131112617 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (131112679) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65556324 + 65556325.

It is an arithmetic number, because the mean of its divisors is an integer number (65556325).

Almost surely, 2131112649 is an apocalyptic number.

It is an amenable number.

131112649 is a deficient number, since it is larger than the sum of its proper divisors (1).

131112649 is an equidigital number, since it uses as much as digits as its factorization.

131112649 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1296, while the sum is 28.

The square root of 131112649 is about 11450.4431791962. The cubic root of 131112649 is about 508.0208428115.

The spelling of 131112649 in words is "one hundred thirty-one million, one hundred twelve thousand, six hundred forty-nine".